x=-3x2+30x+300

Solution for x=-3x2+30x+300 equation:

x=-3x^2+30x+300

We move all terms to the left:

x-(-3x^2+30x+300)=0

We get rid of parentheses

3x^2-30x+x-300=0

We add all the numbers together, and all the variables

3x^2-29x-300=0

a = 3; b = -29; c = -300;
Δ = b2-4ac
Δ = -292-4·3·(-300)
Δ = 4441
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(-29)-\sqrt{4441}}{2*3}=\frac{29-\sqrt{4441}}{6}
$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(-29)+\sqrt{4441}}{2*3}=\frac{29+\sqrt{4441}}{6}
$