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x=-x2-2x-5
We move all terms to the left:
x-(-x2-2x-5)=0
We add all the numbers together, and all the variables
-(-1x^2-2x-5)+x=0
We get rid of parentheses
1x^2+2x+x+5=0
We add all the numbers together, and all the variables
x^2+3x+5=0
a = 1; b = 3; c = +5;
Δ = b2-4ac
Δ = 32-4·1·5
Δ = -11
Delta is less than zero, so there is no solution for the equation
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