x=0.3x2+0.6x-0.7

Solution for x=0.3x2+0.6x-0.7 equation:

x=0.3x^2+0.6x-0.7

We move all terms to the left:

x-(0.3x^2+0.6x-0.7)=0

We get rid of parentheses

-0.3x^2+x-0.6x+0.7=0

We add all the numbers together, and all the variables

-0.3x^2+0.4x+0.7=0

a = -0.3; b = 0.4; c = +0.7;
Δ = b2-4ac
Δ = 0.42-4·(-0.3)·0.7
Δ = 1
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

$\sqrt{\Delta}=\sqrt{1}=1$
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(0.4)-1}{2*-0.3}=\frac{-1.4}{-0.6}
=2+0.2/0.6
$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(0.4)+1}{2*-0.3}=\frac{0.6}{-0.6}
=-1
$