x=1.6x(1-x)

Solution for x=1.6x(1-x) equation:

x=1.6x(1-x)

We move all terms to the left:

x-(1.6x(1-x))=0

We add all the numbers together, and all the variables

x-(1.6x(-1x+1))=0


We calculate terms in parentheses: -(1.6x(-1x+1)), so:

1.6x(-1x+1)

We multiply parentheses

-1x^2+x

Back to the equation:

-(-1x^2+x)


We get rid of parentheses

1x^2-x+x=0

We add all the numbers together, and all the variables

x^2=0

a = 1; b = 0; c = 0;
Δ = b2-4ac
Δ = 02-4·1·0
Δ = 0
Delta is equal to zero, so there is only one solution to the equation

                              Stosujemy wzór:
$x=\frac{-b}{2a}=\frac{0}{2}=0$