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x=1/3x+5500
We move all terms to the left:
x-(1/3x+5500)=0
Domain of the equation: 3x+5500)!=0We get rid of parentheses
x∈R
x-1/3x-5500=0
We multiply all the terms by the denominator
x*3x-5500*3x-1=0
Wy multiply elements
3x^2-16500x-1=0
a = 3; b = -16500; c = -1;
Δ = b2-4ac
Δ = -165002-4·3·(-1)
Δ = 272250012
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$
The end solution:
$\sqrt{\Delta}=\sqrt{272250012}=\sqrt{4*68062503}=\sqrt{4}*\sqrt{68062503}=2\sqrt{68062503}$$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(-16500)-2\sqrt{68062503}}{2*3}=\frac{16500-2\sqrt{68062503}}{6} $$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(-16500)+2\sqrt{68062503}}{2*3}=\frac{16500+2\sqrt{68062503}}{6} $
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