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x=1/5x+495
We move all terms to the left:
x-(1/5x+495)=0
Domain of the equation: 5x+495)!=0We get rid of parentheses
x∈R
x-1/5x-495=0
We multiply all the terms by the denominator
x*5x-495*5x-1=0
Wy multiply elements
5x^2-2475x-1=0
a = 5; b = -2475; c = -1;
Δ = b2-4ac
Δ = -24752-4·5·(-1)
Δ = 6125645
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(-2475)-\sqrt{6125645}}{2*5}=\frac{2475-\sqrt{6125645}}{10} $$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(-2475)+\sqrt{6125645}}{2*5}=\frac{2475+\sqrt{6125645}}{10} $
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