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x=1/5x+8+100
We move all terms to the left:
x-(1/5x+8+100)=0
Domain of the equation: 5x+8+100)!=0We add all the numbers together, and all the variables
We move all terms containing x to the left, all other terms to the right
5x+100)!=-8
x∈R
x-(1/5x+108)=0
We get rid of parentheses
x-1/5x-108=0
We multiply all the terms by the denominator
x*5x-108*5x-1=0
Wy multiply elements
5x^2-540x-1=0
a = 5; b = -540; c = -1;
Δ = b2-4ac
Δ = -5402-4·5·(-1)
Δ = 291620
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$
The end solution:
$\sqrt{\Delta}=\sqrt{291620}=\sqrt{4*72905}=\sqrt{4}*\sqrt{72905}=2\sqrt{72905}$$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(-540)-2\sqrt{72905}}{2*5}=\frac{540-2\sqrt{72905}}{10} $$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(-540)+2\sqrt{72905}}{2*5}=\frac{540+2\sqrt{72905}}{10} $
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