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x=10-5(8/3x)
We move all terms to the left:
x-(10-5(8/3x))=0
Domain of the equation: 3x))!=0We add all the numbers together, and all the variables
x!=0/1
x!=0
x∈R
x-(10-5(+8/3x))=0
We multiply all the terms by the denominator
x*3x))-(10-5(+8=0
Wy multiply elements
3x^2+8=0
a = 3; b = 0; c = +8;
Δ = b2-4ac
Δ = 02-4·3·8
Δ = -96
Delta is less than zero, so there is no solution for the equation
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