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x=10x-4x-5+(2x-25)=
We move all terms to the left:
x-(10x-4x-5+(2x-25))=0
We calculate terms in parentheses: -(10x-4x-5+(2x-25)), so:We get rid of parentheses
10x-4x-5+(2x-25)
determiningTheFunctionDomain 10x-4x+(2x-25)-5
We add all the numbers together, and all the variables
6x+(2x-25)-5
We get rid of parentheses
6x+2x-25-5
We add all the numbers together, and all the variables
8x-30
Back to the equation:
-(8x-30)
x-8x+30=0
We add all the numbers together, and all the variables
-7x+30=0
We move all terms containing x to the left, all other terms to the right
-7x=-30
x=-30/-7
x=4+2/7
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