x=12-2(3+x)

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Solution for x=12-2(3+x) equation: 



x=12-2(3+x)

We move all terms to the left:

x-(12-2(3+x))=0

We add all the numbers together, and all the variables

x-(12-2(x+3))=0



We calculate terms in parentheses: -(12-2(x+3)), so:

12-2(x+3)

determiningTheFunctionDomain
-2(x+3)+12

We multiply parentheses

-2x-6+12

We add all the numbers together, and all the variables

-2x+6

Back to the equation:

-(-2x+6)



We get rid of parentheses

x+2x-6=0

We add all the numbers together, and all the variables

3x-6=0

We move all terms containing x to the left, all other terms to the right

3x=6

x=6/3

x=2

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