x=2(x-1)-3(x-2)-4(x-3)

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Solution for x=2(x-1)-3(x-2)-4(x-3) equation: 



x=2(x-1)-3(x-2)-4(x-3)

We move all terms to the left:

x-(2(x-1)-3(x-2)-4(x-3))=0



We calculate terms in parentheses: -(2(x-1)-3(x-2)-4(x-3)), so:

2(x-1)-3(x-2)-4(x-3)

We multiply parentheses

2x-3x-4x-2+6+12

We add all the numbers together, and all the variables

-5x+16

Back to the equation:

-(-5x+16)



We get rid of parentheses

x+5x-16=0

We add all the numbers together, and all the variables

6x-16=0

We move all terms containing x to the left, all other terms to the right

6x=16

x=16/6

x=2+2/3

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