x=2-2(2x-3+3x)

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Solution for x=2-2(2x-3+3x) equation: 



x=2-2(2x-3+3x)

We move all terms to the left:

x-(2-2(2x-3+3x))=0

We add all the numbers together, and all the variables

x-(2-2(5x-3))=0



We calculate terms in parentheses: -(2-2(5x-3)), so:

2-2(5x-3)

determiningTheFunctionDomain
-2(5x-3)+2

We multiply parentheses

-10x+6+2

We add all the numbers together, and all the variables

-10x+8

Back to the equation:

-(-10x+8)



We get rid of parentheses

x+10x-8=0

We add all the numbers together, and all the variables

11x-8=0

We move all terms containing x to the left, all other terms to the right

11x=8

x=8/11

x=8/11

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