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x=24/3x+2
We move all terms to the left:
x-(24/3x+2)=0
Domain of the equation: 3x+2)!=0We get rid of parentheses
x∈R
x-24/3x-2=0
We multiply all the terms by the denominator
x*3x-2*3x-24=0
Wy multiply elements
3x^2-6x-24=0
a = 3; b = -6; c = -24;
Δ = b2-4ac
Δ = -62-4·3·(-24)
Δ = 324
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$$\sqrt{\Delta}=\sqrt{324}=18$$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(-6)-18}{2*3}=\frac{-12}{6} =-2 $$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(-6)+18}{2*3}=\frac{24}{6} =4 $
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