x=2x2+800x-100

Solution for x=2x2+800x-100 equation:

x=2x^2+800x-100

We move all terms to the left:

x-(2x^2+800x-100)=0

We get rid of parentheses

-2x^2+x-800x+100=0

We add all the numbers together, and all the variables

-2x^2-799x+100=0

a = -2; b = -799; c = +100;
Δ = b2-4ac
Δ = -7992-4·(-2)·100
Δ = 639201
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(-799)-\sqrt{639201}}{2*-2}=\frac{799-\sqrt{639201}}{-4}
$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(-799)+\sqrt{639201}}{2*-2}=\frac{799+\sqrt{639201}}{-4}
$