x=2x2+8x+2

Solution for x=2x2+8x+2 equation:

x=2x^2+8x+2

We move all terms to the left:

x-(2x^2+8x+2)=0

We get rid of parentheses

-2x^2+x-8x-2=0

We add all the numbers together, and all the variables

-2x^2-7x-2=0

a = -2; b = -7; c = -2;
Δ = b2-4ac
Δ = -72-4·(-2)·(-2)
Δ = 33
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(-7)-\sqrt{33}}{2*-2}=\frac{7-\sqrt{33}}{-4}
$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(-7)+\sqrt{33}}{2*-2}=\frac{7+\sqrt{33}}{-4}
$