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x=3+5(x-3)+6x
We move all terms to the left:
x-(3+5(x-3)+6x)=0
We calculate terms in parentheses: -(3+5(x-3)+6x), so:We get rid of parentheses
3+5(x-3)+6x
determiningTheFunctionDomain 5(x-3)+6x+3
We add all the numbers together, and all the variables
6x+5(x-3)+3
We multiply parentheses
6x+5x-15+3
We add all the numbers together, and all the variables
11x-12
Back to the equation:
-(11x-12)
x-11x+12=0
We add all the numbers together, and all the variables
-10x+12=0
We move all terms containing x to the left, all other terms to the right
-10x=-12
x=-12/-10
x=1+1/5
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