x=3.3x(1-x)

Solution for x=3.3x(1-x) equation:

x=3.3x(1-x)

We move all terms to the left:

x-(3.3x(1-x))=0

We add all the numbers together, and all the variables

x-(3.3x(-1x+1))=0


We calculate terms in parentheses: -(3.3x(-1x+1)), so:

3.3x(-1x+1)

We multiply parentheses

-3x^2+3x

Back to the equation:

-(-3x^2+3x)


We get rid of parentheses

3x^2-3x+x=0

We add all the numbers together, and all the variables

3x^2-2x=0

a = 3; b = -2; c = 0;
Δ = b2-4ac
Δ = -22-4·3·0
Δ = 4
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

$\sqrt{\Delta}=\sqrt{4}=2$
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(-2)-2}{2*3}=\frac{0}{6}
=0
$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(-2)+2}{2*3}=\frac{4}{6}
=2/3
$