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x=3/4x-8
We move all terms to the left:
x-(3/4x-8)=0
Domain of the equation: 4x-8)!=0We get rid of parentheses
x∈R
x-3/4x+8=0
We multiply all the terms by the denominator
x*4x+8*4x-3=0
Wy multiply elements
4x^2+32x-3=0
a = 4; b = 32; c = -3;
Δ = b2-4ac
Δ = 322-4·4·(-3)
Δ = 1072
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$
The end solution:
$\sqrt{\Delta}=\sqrt{1072}=\sqrt{16*67}=\sqrt{16}*\sqrt{67}=4\sqrt{67}$$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(32)-4\sqrt{67}}{2*4}=\frac{-32-4\sqrt{67}}{8} $$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(32)+4\sqrt{67}}{2*4}=\frac{-32+4\sqrt{67}}{8} $
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