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x=3/5x+9
We move all terms to the left:
x-(3/5x+9)=0
Domain of the equation: 5x+9)!=0We get rid of parentheses
x∈R
x-3/5x-9=0
We multiply all the terms by the denominator
x*5x-9*5x-3=0
Wy multiply elements
5x^2-45x-3=0
a = 5; b = -45; c = -3;
Δ = b2-4ac
Δ = -452-4·5·(-3)
Δ = 2085
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(-45)-\sqrt{2085}}{2*5}=\frac{45-\sqrt{2085}}{10} $$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(-45)+\sqrt{2085}}{2*5}=\frac{45+\sqrt{2085}}{10} $
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