If it's not what You are looking for type in the equation solver your own equation and let us solve it.
x=32/x
We move all terms to the left:
x-(32/x)=0
Domain of the equation: x)!=0We add all the numbers together, and all the variables
x!=0/1
x!=0
x∈R
x-(+32/x)=0
We get rid of parentheses
x-32/x=0
We multiply all the terms by the denominator
x*x-32=0
Wy multiply elements
x^2-32=0
a = 1; b = 0; c = -32;
Δ = b2-4ac
Δ = 02-4·1·(-32)
Δ = 128
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$
The end solution:
$\sqrt{\Delta}=\sqrt{128}=\sqrt{64*2}=\sqrt{64}*\sqrt{2}=8\sqrt{2}$$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(0)-8\sqrt{2}}{2*1}=\frac{0-8\sqrt{2}}{2} =-\frac{8\sqrt{2}}{2} =-4\sqrt{2} $$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(0)+8\sqrt{2}}{2*1}=\frac{0+8\sqrt{2}}{2} =\frac{8\sqrt{2}}{2} =4\sqrt{2} $
| 3(x-3)+4x+7=5x+4 | | 3(2-6x)=-84 | | 140+28x=14x | | 16x+99=12x-3 | | 3(x-3)+4+7=5x+4 | | 16x+9=12x-3 | | 16x+99=12x-3 | | -5(8n-5)=225 | | 5(a-1)-3(2-a)=3(2a-4)+2(25-5a) | | j-(5j+-3j)=7j+4 | | 60=n=8 | | X2+4x+4=9 | | 60(n)=8 | | 5(f+2)=12+5f-3 | | (X+6)(6x+5)=0 | | 48r-12=28 | | 3y-8+13=4y | | 3k-10=5(k+1) | | -2/3x+15=17 | | 4x-2x=7-1 | | 5=y+29/8 | | O.3(4z-6)=0.5(2z+9) | | 10=g-46/4 | | 0=35-7(x=2) | | 11=19-4d | | (2+3x)*2+(2-3x)*2=26 | | -4(2+7x)=160 | | 5t=3t+3 | | (2+3x)^2+(2-3x)^2=26 | | 2c-2(3-8c)=3c-48 | | (2x+3x)^2+(2-3x)^2=26 | | 15x=8x+14x |