x=35x-3/4+5(x+5)+3(13-2x)

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Solution for x=35x-3/4+5(x+5)+3(13-2x) equation: 



x=35x-3/4+5(x+5)+3(13-2x)

We move all terms to the left:

x-(35x-3/4+5(x+5)+3(13-2x))=0



Domain of the equation: 4+5(x+5)+3(13-2x))!=0

We move all terms containing x to the left, all other terms to the right

5(x+5)+3(13-2x))!=-4

x∈R



We add all the numbers together, and all the variables

x-(35x-3/4+5(x+5)+3(-2x+13))=0

We multiply all the terms by the denominator


x*4+5(x+5)+3(-2x+13))-(35x-3=0

We multiply parentheses

x*4+5x+3(-2x+13))-(35x+25-3=0

Wy multiply elements

4x+5x+3(-2x+13))-(35x+25-3=0

We add all the numbers together, and all the variables

9x+3(-2x+13))-(35x+22=0

We move all terms containing x to the left, all other terms to the right

9x+3(-2x+13))-(35x=-22

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