x=35x2/5

Solution for x=35x2/5 equation:

x=35x^2/5

We move all terms to the left:

x-(35x^2/5)=0

We get rid of parentheses

-35x^2/5+x=0

We multiply all the terms by the denominator


-35x^2+x*5=0

Wy multiply elements

-35x^2+5x=0

a = -35; b = 5; c = 0;
Δ = b2-4ac
Δ = 52-4·(-35)·0
Δ = 25
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

$\sqrt{\Delta}=\sqrt{25}=5$
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(5)-5}{2*-35}=\frac{-10}{-70}
=1/7
$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(5)+5}{2*-35}=\frac{0}{-70}
=0
$