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x=3x-1/2x+5
We move all terms to the left:
x-(3x-1/2x+5)=0
Domain of the equation: 2x+5)!=0We get rid of parentheses
x∈R
x-3x+1/2x-5=0
We multiply all the terms by the denominator
x*2x-3x*2x-5*2x+1=0
Wy multiply elements
2x^2-6x^2-10x+1=0
We add all the numbers together, and all the variables
-4x^2-10x+1=0
a = -4; b = -10; c = +1;
Δ = b2-4ac
Δ = -102-4·(-4)·1
Δ = 116
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$
The end solution:
$\sqrt{\Delta}=\sqrt{116}=\sqrt{4*29}=\sqrt{4}*\sqrt{29}=2\sqrt{29}$$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(-10)-2\sqrt{29}}{2*-4}=\frac{10-2\sqrt{29}}{-8} $$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(-10)+2\sqrt{29}}{2*-4}=\frac{10+2\sqrt{29}}{-8} $
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