x=4-(x+2)-3(x+4)

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Solution for x=4-(x+2)-3(x+4) equation: 



x=4-(x+2)-3(x+4)

We move all terms to the left:

x-(4-(x+2)-3(x+4))=0



We calculate terms in parentheses: -(4-(x+2)-3(x+4)), so:

4-(x+2)-3(x+4)

determiningTheFunctionDomain
-(x+2)-3(x+4)+4

We multiply parentheses

-(x+2)-3x-12+4

We get rid of parentheses

-x-3x-2-12+4

We add all the numbers together, and all the variables

-4x-10

Back to the equation:

-(-4x-10)



We get rid of parentheses

x+4x+10=0

We add all the numbers together, and all the variables

5x+10=0

We move all terms containing x to the left, all other terms to the right

5x=-10

x=-10/5

x=-2

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