x=4/3,x=-3

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Solution for x=4/3,x=-3 equation:



x=4/3.x=-3
We move all terms to the left:
x-(4/3.x)=0
Domain of the equation: 3.x)!=0
x!=0/1
x!=0
x∈R
We add all the numbers together, and all the variables
x-(+4/3.x)=0
We get rid of parentheses
x-4/3.x=0
We multiply all the terms by the denominator
x*3.x-4=0
Wy multiply elements
3x^2-4=0
a = 3; b = 0; c = -4;
Δ = b2-4ac
Δ = 02-4·3·(-4)
Δ = 48
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

The end solution:
$\sqrt{\Delta}=\sqrt{48}=\sqrt{16*3}=\sqrt{16}*\sqrt{3}=4\sqrt{3}$
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(0)-4\sqrt{3}}{2*3}=\frac{0-4\sqrt{3}}{6} =-\frac{4\sqrt{3}}{6} =-\frac{2\sqrt{3}}{3} $
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(0)+4\sqrt{3}}{2*3}=\frac{0+4\sqrt{3}}{6} =\frac{4\sqrt{3}}{6} =\frac{2\sqrt{3}}{3} $

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