x=40/x-3

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Solution for x=40/x-3 equation:


D( x )

x = 0

x = 0

x = 0

x in (-oo:0) U (0:+oo)

x = 40/x-3 // - 40/x-3

x-(40/x)+3 = 0

x-40*x^-1+3 = 0

1*x^1-40*x^-1+3*x^0 = 0

(1*x^2+3*x^1-40*x^0)/(x^1) = 0 // * x^2

x^1*(1*x^2+3*x^1-40*x^0) = 0

x^1

x^2+3*x-40 = 0

x^2+3*x-40 = 0

DELTA = 3^2-(-40*1*4)

DELTA = 169

DELTA > 0

x = (169^(1/2)-3)/(1*2) or x = (-169^(1/2)-3)/(1*2)

x = 5 or x = -8

x in { -8, 5}

x in { -8, 5 }

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