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x=5(x-12)+15(3+x)
We move all terms to the left:
x-(5(x-12)+15(3+x))=0
We add all the numbers together, and all the variables
x-(5(x-12)+15(x+3))=0
We calculate terms in parentheses: -(5(x-12)+15(x+3)), so:We get rid of parentheses
5(x-12)+15(x+3)
We multiply parentheses
5x+15x-60+45
We add all the numbers together, and all the variables
20x-15
Back to the equation:
-(20x-15)
x-20x+15=0
We add all the numbers together, and all the variables
-19x+15=0
We move all terms containing x to the left, all other terms to the right
-19x=-15
x=-15/-19
x=15/19
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