x=5+19x2

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Solution for x=5+19x2 equation: 



x=5+19x^2

We move all terms to the left:

x-(5+19x^2)=0

We get rid of parentheses

-19x^2+x-5=0

a = -19; b = 1; c = -5;
Δ = b2-4ac
Δ = 12-4·(-19)·(-5)
Δ = -379
Delta is less than zero, so there is no solution for the equation

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