x=5,x2+2(x+6)

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Solution for x=5,x2+2(x+6) equation: 



x=5.x^2+2(x+6)

We move all terms to the left:

x-(5.x^2+2(x+6))=0



We calculate terms in parentheses: -(5.x^2+2(x+6)), so:

5.x^2+2(x+6)

We multiply parentheses

5.x^2+2x+12

Back to the equation:

-(5.x^2+2x+12)



We get rid of parentheses

-5.x^2+x-2x-12=0

We add all the numbers together, and all the variables

-5x^2-1x-12=0

a = -5; b = -1; c = -12;
Δ = b2-4ac
Δ = -12-4·(-5)·(-12)
Δ = -239
Delta is less than zero, so there is no solution for the equation

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