x=5,x2+3(x+3)

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Solution for x=5,x2+3(x+3) equation: 



x=5.x^2+3(x+3)

We move all terms to the left:

x-(5.x^2+3(x+3))=0



We calculate terms in parentheses: -(5.x^2+3(x+3)), so:

5.x^2+3(x+3)

We multiply parentheses

5.x^2+3x+9

Back to the equation:

-(5.x^2+3x+9)



We get rid of parentheses

-5.x^2+x-3x-9=0

We add all the numbers together, and all the variables

-5x^2-2x-9=0

a = -5; b = -2; c = -9;
Δ = b2-4ac
Δ = -22-4·(-5)·(-9)
Δ = -176
Delta is less than zero, so there is no solution for the equation

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