x=5/(4x-5)

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Solution for x=5/(4x-5) equation:


D( x )

4*x-5 = 0

4*x-5 = 0

4*x-5 = 0

4*x-5 = 0 // + 5

4*x = 5 // : 4

x = 5/4

x in (-oo:5/4) U (5/4:+oo)

x = 5/(4*x-5) // - 5/(4*x-5)

x-(5/(4*x-5)) = 0

x-5*(4*x-5)^-1 = 0

x-5/(4*x-5) = 0

(x*(4*x-5))/(4*x-5)-5/(4*x-5) = 0

x*(4*x-5)-5 = 0

4*x^2-5*x-5 = 0

4*x^2-5*x-5 = 0

4*x^2-5*x-5 = 0

DELTA = (-5)^2-(-5*4*4)

DELTA = 105

DELTA > 0

x = (105^(1/2)+5)/(2*4) or x = (5-105^(1/2))/(2*4)

x = (105^(1/2)+5)/8 or x = (5-105^(1/2))/8

(x-((5-105^(1/2))/8))*(x-((105^(1/2)+5)/8)) = 0

((x-((5-105^(1/2))/8))*(x-((105^(1/2)+5)/8)))/(4*x-5) = 0

((x-((5-105^(1/2))/8))*(x-((105^(1/2)+5)/8)))/(4*x-5) = 0 // * 4*x-5

(x-((5-105^(1/2))/8))*(x-((105^(1/2)+5)/8)) = 0

( x-((105^(1/2)+5)/8) )

x-((105^(1/2)+5)/8) = 0 // + (105^(1/2)+5)/8

x = (105^(1/2)+5)/8

( x-((5-105^(1/2))/8) )

x-((5-105^(1/2))/8) = 0 // + (5-105^(1/2))/8

x = (5-105^(1/2))/8

x in { (105^(1/2)+5)/8, (5-105^(1/2))/8 }

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