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x=5/3x+8
We move all terms to the left:
x-(5/3x+8)=0
Domain of the equation: 3x+8)!=0We get rid of parentheses
x∈R
x-5/3x-8=0
We multiply all the terms by the denominator
x*3x-8*3x-5=0
Wy multiply elements
3x^2-24x-5=0
a = 3; b = -24; c = -5;
Δ = b2-4ac
Δ = -242-4·3·(-5)
Δ = 636
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$
The end solution:
$\sqrt{\Delta}=\sqrt{636}=\sqrt{4*159}=\sqrt{4}*\sqrt{159}=2\sqrt{159}$$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(-24)-2\sqrt{159}}{2*3}=\frac{24-2\sqrt{159}}{6} $$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(-24)+2\sqrt{159}}{2*3}=\frac{24+2\sqrt{159}}{6} $
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