x=56+(2x/9)

Solution for x=56+(2x/9) equation:

x=56+(2x/9)

We move all terms to the left:

x-(56+(2x/9))=0

We add all the numbers together, and all the variables

x-(56+(+2x/9))=0

We multiply all the terms by the denominator


x*9))-(56+(+2x=0

We add all the numbers together, and all the variables

2x+x*9))-(56+(=0

Wy multiply elements

9x^2+2x=0

a = 9; b = 2; c = 0;
Δ = b2-4ac
Δ = 22-4·9·0
Δ = 4
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

$\sqrt{\Delta}=\sqrt{4}=2$
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(2)-2}{2*9}=\frac{-4}{18}
=-2/9
$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(2)+2}{2*9}=\frac{0}{18}
=0
$