x=5x2+20x+16

Solution for x=5x2+20x+16 equation:

x=5x^2+20x+16

We move all terms to the left:

x-(5x^2+20x+16)=0

We get rid of parentheses

-5x^2+x-20x-16=0

We add all the numbers together, and all the variables

-5x^2-19x-16=0

a = -5; b = -19; c = -16;
Δ = b2-4ac
Δ = -192-4·(-5)·(-16)
Δ = 41
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(-19)-\sqrt{41}}{2*-5}=\frac{19-\sqrt{41}}{-10}
$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(-19)+\sqrt{41}}{2*-5}=\frac{19+\sqrt{41}}{-10}
$