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x=5x^2+5x+12
We move all terms to the left:
x-(5x^2+5x+12)=0
We get rid of parentheses
-5x^2+x-5x-12=0
We add all the numbers together, and all the variables
-5x^2-4x-12=0
a = -5; b = -4; c = -12;
Δ = b2-4ac
Δ = -42-4·(-5)·(-12)
Δ = -224
Delta is less than zero, so there is no solution for the equation
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