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x=5x^2-20x-20=0
We move all terms to the left:
x-(5x^2-20x-20)=0
We get rid of parentheses
-5x^2+x+20x+20=0
We add all the numbers together, and all the variables
-5x^2+21x+20=0
a = -5; b = 21; c = +20;
Δ = b2-4ac
Δ = 212-4·(-5)·20
Δ = 841
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$$\sqrt{\Delta}=\sqrt{841}=29$$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(21)-29}{2*-5}=\frac{-50}{-10} =+5 $$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(21)+29}{2*-5}=\frac{8}{-10} =-4/5 $
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