x=60-3x(2x+x)

Solution for x=60-3x(2x+x) equation:

x=60-3x(2x+x)

We move all terms to the left:

x-(60-3x(2x+x))=0

We add all the numbers together, and all the variables

x-(60-3x(+3x))=0


We calculate terms in parentheses: -(60-3x(+3x)), so:

60-3x(+3x)

determiningTheFunctionDomain
-3x(+3x)+60

We multiply parentheses

-9x^2+60

Back to the equation:

-(-9x^2+60)


We get rid of parentheses

9x^2+x-60=0

a = 9; b = 1; c = -60;
Δ = b2-4ac
Δ = 12-4·9·(-60)
Δ = 2161
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(1)-\sqrt{2161}}{2*9}=\frac{-1-\sqrt{2161}}{18}
$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(1)+\sqrt{2161}}{2*9}=\frac{-1+\sqrt{2161}}{18}
$