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x=6x-2/2x+8
We move all terms to the left:
x-(6x-2/2x+8)=0
Domain of the equation: 2x+8)!=0We get rid of parentheses
x∈R
x-6x+2/2x-8=0
We multiply all the terms by the denominator
x*2x-6x*2x-8*2x+2=0
Wy multiply elements
2x^2-12x^2-16x+2=0
We add all the numbers together, and all the variables
-10x^2-16x+2=0
a = -10; b = -16; c = +2;
Δ = b2-4ac
Δ = -162-4·(-10)·2
Δ = 336
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$
The end solution:
$\sqrt{\Delta}=\sqrt{336}=\sqrt{16*21}=\sqrt{16}*\sqrt{21}=4\sqrt{21}$$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(-16)-4\sqrt{21}}{2*-10}=\frac{16-4\sqrt{21}}{-20} $$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(-16)+4\sqrt{21}}{2*-10}=\frac{16+4\sqrt{21}}{-20} $
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