x=8(x+5)8x+35

Solution for x=8(x+5)8x+35 equation:

x=8(x+5)8x+35

We move all terms to the left:

x-(8(x+5)8x+35)=0


We calculate terms in parentheses: -(8(x+5)8x+35), so:

8(x+5)8x+35

We multiply parentheses

64x^2+320x+35

Back to the equation:

-(64x^2+320x+35)


We get rid of parentheses

-64x^2+x-320x-35=0

We add all the numbers together, and all the variables

-64x^2-319x-35=0

a = -64; b = -319; c = -35;
Δ = b2-4ac
Δ = -3192-4·(-64)·(-35)
Δ = 92801
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(-319)-\sqrt{92801}}{2*-64}=\frac{319-\sqrt{92801}}{-128}
$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(-319)+\sqrt{92801}}{2*-64}=\frac{319+\sqrt{92801}}{-128}
$