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x=8x^2-6x-35
We move all terms to the left:
x-(8x^2-6x-35)=0
We get rid of parentheses
-8x^2+x+6x+35=0
We add all the numbers together, and all the variables
-8x^2+7x+35=0
a = -8; b = 7; c = +35;
Δ = b2-4ac
Δ = 72-4·(-8)·35
Δ = 1169
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(7)-\sqrt{1169}}{2*-8}=\frac{-7-\sqrt{1169}}{-16} $$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(7)+\sqrt{1169}}{2*-8}=\frac{-7+\sqrt{1169}}{-16} $
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