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x=99+1/5x
We move all terms to the left:
x-(99+1/5x)=0
Domain of the equation: 5x)!=0We add all the numbers together, and all the variables
x!=0/1
x!=0
x∈R
x-(1/5x+99)=0
We get rid of parentheses
x-1/5x-99=0
We multiply all the terms by the denominator
x*5x-99*5x-1=0
Wy multiply elements
5x^2-495x-1=0
a = 5; b = -495; c = -1;
Δ = b2-4ac
Δ = -4952-4·5·(-1)
Δ = 245045
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(-495)-\sqrt{245045}}{2*5}=\frac{495-\sqrt{245045}}{10} $$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(-495)+\sqrt{245045}}{2*5}=\frac{495+\sqrt{245045}}{10} $
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