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x=x2-17/25
We move all terms to the left:
x-(x2-17/25)=0
We add all the numbers together, and all the variables
-(+x^2-17/25)+x=0
We get rid of parentheses
-x^2+x+17/25=0
We multiply all the terms by the denominator
-x^2*25+x*25+17=0
Wy multiply elements
-25x^2+25x+17=0
a = -25; b = 25; c = +17;
Δ = b2-4ac
Δ = 252-4·(-25)·17
Δ = 2325
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$
The end solution:
$\sqrt{\Delta}=\sqrt{2325}=\sqrt{25*93}=\sqrt{25}*\sqrt{93}=5\sqrt{93}$$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(25)-5\sqrt{93}}{2*-25}=\frac{-25-5\sqrt{93}}{-50} $$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(25)+5\sqrt{93}}{2*-25}=\frac{-25+5\sqrt{93}}{-50} $
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