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xx(x-9)=90
We move all terms to the left:
xx(x-9)-(90)=0
We multiply parentheses
x^2-9x-90=0
a = 1; b = -9; c = -90;
Δ = b2-4ac
Δ = -92-4·1·(-90)
Δ = 441
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$$\sqrt{\Delta}=\sqrt{441}=21$$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(-9)-21}{2*1}=\frac{-12}{2} =-6 $$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(-9)+21}{2*1}=\frac{30}{2} =15 $
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