y(10-y)=40

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Solution for y(10-y)=40 equation: 



y(10-y)=40

We move all terms to the left:

y(10-y)-(40)=0

We add all the numbers together, and all the variables

y(-1y+10)-40=0

We multiply parentheses

-1y^2+10y-40=0

a = -1; b = 10; c = -40;
Δ = b2-4ac
Δ = 102-4·(-1)·(-40)
Δ = -60
Delta is less than zero, so there is no solution for the equation

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