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y(2)=3y(2-1)-2*4(2-2)+5
We move all terms to the left:
y(2)-(3y(2-1)-2*4(2-2)+5)=0
We add all the numbers together, and all the variables
y2-(3y1-2*40+5)=0
We add all the numbers together, and all the variables
y^2-(3y1-2*40+5)=0
We get rid of parentheses
y^2-3y1-5+2*40=0
We add all the numbers together, and all the variables
y^2-3y+75=0
a = 1; b = -3; c = +75;
Δ = b2-4ac
Δ = -32-4·1·75
Δ = -291
Delta is less than zero, so there is no solution for the equation
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