y(2-y)=6-(y*y+3y-4)

Solution for y(2-y)=6-(y*y+3y-4) equation:

y(2-y)=6-(y*y+3y-4)

We move all terms to the left:

y(2-y)-(6-(y*y+3y-4))=0

We add all the numbers together, and all the variables

y(-1y+2)-(6-(3y+y*y-4))=0

We multiply parentheses

-1y^2+2y-(6-(3y+y*y-4))=0


We calculate terms in parentheses: -(6-(3y+y*y-4)), so:

6-(3y+y*y-4)

determiningTheFunctionDomain
-(3y+y*y-4)+6

We get rid of parentheses

-3y-y*y+4+6

We add all the numbers together, and all the variables

-3y-y*y+10

Wy multiply elements

-1y^2-3y+10

Back to the equation:

-(-1y^2-3y+10)


We get rid of parentheses

-1y^2+1y^2+3y+2y-10=0

We add all the numbers together, and all the variables

5y-10=0

We move all terms containing y to the left, all other terms to the right

5y=10

y=10/5

y=2