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y(2-y)=6-(y2+3y-4)
We move all terms to the left:
y(2-y)-(6-(y2+3y-4))=0
We add all the numbers together, and all the variables
-(6-(+y^2+3y-4))+y(-1y+2)=0
We multiply parentheses
-(6-(+y^2+3y-4))-1y^2+2y=0
We calculate terms in parentheses: -(6-(+y^2+3y-4)), so:We add all the numbers together, and all the variables
6-(+y^2+3y-4)
determiningTheFunctionDomain -(+y^2+3y-4)+6
We get rid of parentheses
-y^2-3y+4+6
We add all the numbers together, and all the variables
-1y^2-3y+10
Back to the equation:
-(-1y^2-3y+10)
-1y^2-(-1y^2-3y+10)+2y=0
We get rid of parentheses
-1y^2+1y^2+3y+2y-10=0
We add all the numbers together, and all the variables
5y-10=0
We move all terms containing y to the left, all other terms to the right
5y=10
y=10/5
y=2
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