y(24+5y)=0

Solution for y(24+5y)=0 equation:

y(24+5y)=0

We add all the numbers together, and all the variables

y(5y+24)=0

We multiply parentheses

5y^2+24y=0

a = 5; b = 24; c = 0;
Δ = b2-4ac
Δ = 242-4·5·0
Δ = 576
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$y_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$y_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

$\sqrt{\Delta}=\sqrt{576}=24$
$y_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(24)-24}{2*5}=\frac{-48}{10}
=-4+4/5
$
$y_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(24)+24}{2*5}=\frac{0}{10}
=0
$