y(2y-3)-2y(y-5)=26

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Solution for y(2y-3)-2y(y-5)=26 equation: 



(2Y-3)-2Y(Y-5)=26

We move all terms to the left:

(2Y-3)-2Y(Y-5)-(26)=0

We multiply parentheses

-2Y^2+(2Y-3)+10Y-26=0

We get rid of parentheses

-2Y^2+2Y+10Y-3-26=0

We add all the numbers together, and all the variables

-2Y^2+12Y-29=0

a = -2; b = 12; c = -29;
Δ = b2-4ac
Δ = 122-4·(-2)·(-29)
Δ = -88
Delta is less than zero, so there is no solution for the equation

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