y(3/4)-6=y(1/4)+10

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Solution for y(3/4)-6=y(1/4)+10 equation:



y(3/4)-6=y(1/4)+10
We move all terms to the left:
y(3/4)-6-(y(1/4)+10)=0
We add all the numbers together, and all the variables
y(+3/4)-(y(+1/4)+10)-6=0
We multiply parentheses
3y^2-(y(+1/4)+10)-6=0
We multiply all the terms by the denominator
3y^2*4)+10)-(y(+1-6*4)+10)=0
We add all the numbers together, and all the variables
3y^2*4)+10)-(y(-23)+10)=0
We add all the numbers together, and all the variables
3y^2*4)+10)-(y(=0
Wy multiply elements
12y^3=0
We do not support eypression: y^3

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